If x + y = 4, then find the value of x3 + y3 + 12xy – 64.
Answer :
It is given that
x + y = 4
By cubing on both sides
(x + y)3 = 43
Expanding using formula
x3 + y3 + 3xy (x + y) = 64
Substituting the value of x + y
x3 + y3 + 3xy (4) = 64
So we get
x3 + y3 + 12xy – 64 = 0
Hence, the value of x3 + y3 + 12xy – 64 is 0.
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