Find the value of x3 + y3 + 12xy – 64.

If x + y = 4, then find the value of x3 + y3 + 12xy – 64.

Answer :

It is given that

x + y = 4

By cubing on both sides

(x + y)3 = 43

Expanding using formula

x3 + y3 + 3xy (x + y) = 64

Substituting the value of x + y

x3 + y3 + 3xy (4) = 64

So we get

x3 + y3 + 12xy – 64 = 0

Hence, the value of x3 + y3 + 12xy – 64 is 0.

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