Find the values of (sin30°/cos245°) – 3tan30° + 5cos90°

Find the values of

(i) (sin30°/cos²45°) – 3tan30° + 5cos90°

(ii) 2√2 cos45° cos60° + 2√3 sin30° tan60° – cos30°

(iii) 4/5 tan²60° – (2/sin²30°) – 3/4 tan²30°

Answer :

= 0

(ii) 2√2 cos 45° cos 60° + 2√3 sin 30° tan 60° – cos 0°

= 2√2 × 1/√2 × ½ + 2√3 × ½ × √3 – 1

= 2 × 1/1 × 1/2 + 2 × 3 × ½ – 1

= 1 + 3 – 1

= 3

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