From 3×2 – 4y2 + 5xy + 20 to obtain -x2 – y2 + 6xy + 20 ?

What should be taken away from 3x² – 4y² + 5xy + 20 to obtain -x² – y² + 6xy + 20?

Solution:

From the sum of 2y² + 3yz, -y² – yz – z² and yz + 2z², subtract the sum of 3y² – z² and -y² + yz + z².

Solution:

More Solutions:

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