(a) In the figure (1) given below, ABC is an equilateral triangle with each side of length 10 cm. In ∆ BCD, ∠D = 90° and CD = 6 cm.
Find the area of the shaded region. Give your answer correct to one decimal place.
(b) In the figure given, ABC is an isosceles right angled triangle and DEFG is a rectangle. If AD = AE = 3 cm and DB = EC = 4 cm, find the area of the shaded region.
Solution:
More Solutions:
- Find the area of quadrilateral.
- Find the area of the quadrilateral field ABCD.
- ACD is an equilateral triangle of side 12 cm.
- AB = 6 cm, BC = 8 cm 13 and CD = AD = 13 cm.
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