(a) In the figure (i) given below, AB is a diameter of a circle with centre O. AC and BD are perpendiculars on a line PQ. BD meets the circle at E. Prove that AC = ED.
(b) In the figure (ii) given below, O is the centre of a circle. Chord CD is parallel to the diameter AB. If ∠ABC = 25°, calculate ∠CED.
Solution:
More Solutions:
- If the area of two similar triangles are 360 cm² and 250 cm².
- In the adjoining figure, D is a point on BC.
- In the adjoining figure, the diagonals of a parallelogram intersect at O.
- E is mid-point of BC. DE meets the diagonal AC at O.
- A point moves such that its distance from a fixed line AB.
- P is a fixed point and a point Q moves such that the distance PQ.