(a) In the figure (1) given below. ∠AED = ∠ABC. Find the values of x and y.
(b) In the fig. (2) given below, CD = 
AC, B is mid-point of AC and E is mid-point of DF. If BF || AG, prove that:
(i) CE || AG
(ii) 3ED = GD.
Solution:
More Solutions:
- CM and RN are respectively the medians of ∆ABC and ∆PQR.
- Medians AD and BE of ∆ABC meet at the point G.
- In the figure given below, AB, EF and CD are parallel lines.
- ∠A = 90° and AD ⊥ BC If BD = 2 cm and CD = 8 cm.
- A 15-meter high tower casts a shadow of 24 meters.
- In the figure, DE parallel BG, AD = 3 cm, BD = 4 cm and BC = 5 cm.