(a) In the figure (i) given below, chords AB and CD of a circle intersect at E.
(i) Prove that triangles ADE and CBE are similar.
(ii) Given DC =12 cm, DE = 4 cm and AE = 16 cm, calculate the length of BE.
(b) In the figure (ii) given below, AB and CD are two intersecting chords of a circle. Name two triangles which are similar. Hence, calculate CP given that AP = 6 cm, PB = 4 cm, and CD = 14 cm (PC > PD).
Solution:
More Solutions:
- If the area of two similar triangles are 360 cm² and 250 cm².
- In the adjoining figure, D is a point on BC.
- In the adjoining figure, the diagonals of a parallelogram intersect at O.
- E is mid-point of BC. DE meets the diagonal AC at O.
- A point moves such that its distance from a fixed line AB.
- P is a fixed point and a point Q moves such that the distance PQ.