If a = cz, b = ax and c = by, prove that xyz = 1.

If a = c^z, b = a^x and c = b^y, prove that xyz = 1.

Solution:

It is given that

a = c^z, b = a^x and c = b^y

We can write it as

a = (b^y)^z where c = b^y

So we get

a = b^yz

Here

a = (a^x)^yz

a¹ = a^xyz

By comparing both

xyz = 1

Therefore, it is proved.

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