If a kite is flying at a height of 40 √3 metres.

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If a kite is flying at a height of 40 √3 metres from the level-ground, attached to a string inclined at 60° to the horizontal, then the length of the string is
(a) 80 m
(b) 60 √3 m
(c) 80 √3 m
(d) 120 m

Solution:

Let K is kite
Height of KT = 40 √3 m
Angle of elevation of string at the ground = 60°
Let length of string AK = x m

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 20 Heights and Distances MCQS Q3.1

The top of a broken tree has its top touching the ground (shown in the given figure) at a distance of 10 m from the bottom. If the angle made by the broken part with ground is 30°, then the length of the broken part is
(a) 10 √3 m
(b) \frac { 20 }{ \sqrt { 3 } }
(c) 20 m
(d) 20 √3 m

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 20 Heights and Distances MCQS Q4.1

Solution:

From the figure, AC is the height of tree and from B, it was broken
AB = A’C
Angle of elevation = 30°
A’C = 10 m
Let AC = hm’
and A’B = x m
BC = h – x m
cos\theta =\frac { A'C }{ A'B }
cos{ 30 }^{ o }=\frac { 10 }{ x }

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 20 Heights and Distances MCQS Q4.2

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