If a pole 6 m high casts shadow 2 √3 m.

If a pole 6 m high casts a shadow 2 √3 m long on the ground, then the sun’s elevation is
(a) 60°
(b) 45°
(c) 30°
(d) 90°

Solution:

Height of pole AB = 6 m
and its shadow BC = 2√3 m

If the length of the shadow of a tower is √3 times that of its height, then the angle of elevation of the sun is
(a) 15°
(b) 30°
(c) 45°
(d) 60°

Solution:

Let height of a tower AB = h m
Then its shadow BC = √3 hm

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