If a2 + b2 = 13 and ab = 6, find
(i) a + b
(ii) a – b
Answer :
(i) We know that
(a + b)2 = a2 + b2 + 2ab
Substituting the values
= 13 + 2 × 6
So we get
= 13 + 12
= 25
Here
a + b = ± √25 = ± 5
(ii) We know that
(a – b)2 = a2 + b2 – 2ab
Substituting the values
= 13 – 2 × 6
So we get
= 13 – 12
= 1
Here
a – b = ± √1 = ± 1
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