**In the adjoining figure, ABCD is a rhombus and DCFE is a square. If ∠ABC = 56°, find**

**(i) ∠DAG**

**(ii) ∠FEG**

**(iii) ∠GAC**

**(iv) ∠AGC.**

**Solution:**

**More Solutions:**

- Prove that: Area of ∆ABP + area of ∆DPC = Area of ∆APD.
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- Prove that: area of || gm ABCD + area of || gm AEFB = area of || gm EFCD.