The diagonals AC and BD of a rhombus ABCD meet at O. If AC = 8 cm and BD = 6 cm, find sin ∠OCD.
Answer :
Diagonals AC and BD of rhombus ABCD meet at O
AC = 8 cm and BD = 6 cm
O is the mid point of AC
AO = OC = AC/2 = 8/2 = 4 cm
O is the mid point of BD
BO = OD = BD/2 = 6/2 = 3 cm
In right angled ∆COD
CD2 = OC2 + OD2
CD2 = 42 + 32
CD2 = 16 + 9 = 25
⇒ CD2 = 52
⇒ CD = 5 cm
In right angled ∆COD
sin ∠OCD = perpendicular/ hypotenuse
sin ∠OCD = OD/CD = 3/5
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