In the given figure, O is the center of the circle. If ∠AOB = 90° and ∠ABC = 30°, then ∠CAO is equal to
(a) 30°
(b) 45°
(c) 90°
(d) 60°
Solution:
More Solutions:
- In the figure given below, O is the centre of the circle.
- Given below, PQ is a diameter. Chord SR is parallel to PQ.
- AB is a diameter of the circle. If ∠ADC = 120°, find ∠CAB.
- ABCD is a quadrilateral inscribed in a circle with centre O.
- PQRS is a cyclic quadrilateral in which PQ = QR and RS is produced to T.
- Given below, O is the centre of the circle.