If ax3 + 3×2 + bx – 3 has a factor (2x + 3) and leaves remainder – 3

If ax³ + 3x² + bx – 3 has a factor (2x + 3) and leaves remainder – 3 when divided by (x + 2), find the values of a and 6. With these values of a and 6, factorize the given expression.

Solution:

Given f(x) = ax² + bx + 2 and g(x) = bx² + ax + 1. If x – 2 is a factor of f(x) but leaves the remainder – 15 when it divides g(x), find the values of a and b. With these values of a and b, factorise the expression. f(x) + g(x) + 4x² + 7x.

Solution:

More Solutions:

• Solve the following equation by factorization x² + 6x – 16 = 0
• Solve the following equation by factorization x(x + 1) + (x + 2)(x + 3) = 42
• Solve the following equation by factorization √x+15 = x + 3
• Solve the following equation by factorization 2x² – 3x – 1 = 0