∆ABC ~ ∆DEF. If BC = 3 cm, EF = 4 cm and area of ∆ABC = 54 sq. cm. Determine the area of ∆DEF.
Solution:
The area of two similar triangles is 36 cm² and 25 cm². If an altitude of the first triangle is 2.4 cm, find the corresponding altitude of the other triangle.
Solution:
More Solutions:
- DE parallel BC. If DE = 6 cm, BC = 9 cm and area of ∆ADE = 28 sq. cm
- Prove that ∆ADE and ∆ABC are similar.
- In the given figure, AB and DE are perpendicular to BC.
- In the adjoining figure, ABC is a triangle. DE is parallel to BC.
- In ∆ABC, AP: PB = 2 : 3. PO is parallel to BC and is extended to Q so that CQ is parallel to BA.
- Determine the ratio of the areas of ∆AOB and ∆COD.