If tangents PA and PB from an exterior point P to a circle with centre O are inclined to each other at an angle of 80°, then ∠POA is equal to
(a) 50°
(b) 60°
(c) 70°
(d) 100°
Solution:
In the given figure, PA and PB are tangents from point P to a circle with centre O. If the radius of the circle is 5 cm and PA ⊥ PB, then the length OP is equal to
(a) 5 cm
(b) 10 cm
(c) 7.5 cm
(d) 5√2 cm
Solution:
More Solutions:
- A point P is 13 cm from the center of a circle.
- From a point outside a circle, with center O, tangents PA and PB are drawn.
- The figure given below shows two circles with centres A, B.
- Two circles with centers A and B touch externally.
- Two chords AB, CD of a circle intersect externally at a point P.
- Chord AB and diameter CD of a circle with centre O meet at P.