If the line 3x – 4y + 7 = 0 and 2x + ky + 5 = 0 are perpendicular.

If the line 3x – 4y + 7 = 0 and 2x + ky + 5 = 0 are perpendicular to each other, then the value of k is
(a) \\ \frac { 3 }{ 2 }
(b) - \frac { 3 }{ 2 }
(c) \\ \frac { 2 }{ 3 }
(d) - \frac { 2 }{ 3 }

Solution:

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 12 Equation of a Straight Line MCQS

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