If x + 1/x = 4, find the values of
(i) x2 + 1/x2
(ii) x4 + 1/x4
(iii) x3 + 1/x3
(iv) x – 1/x.
Answer :
(i) We know that
(x + 1/x)2 = x2 + 1/x2 + 2
It can be written as
x2 + 1/x2 = (x + 1/x)2 – 2
Substituting the values
= 42 – 2
= 16 – 2
= 14
(ii) We know that
(x2 + 1/x2)2 = x4 + 1/x4 + 2
It can be written as
x4 + 1/x4 = (x2 + 1/x2)2 – 2
Substituting the values
= 142 – 2
= 196 – 2
= 194
(iii) We know that
x3 + 1/x3 = (x + 1/x)3 – 3x (1/x) (x + 1/x)
It can be written as
(x + 1/x)3 – 3(x + 1/x) = 43 – 3 × 4
By further calculation
= 64 – 12
= 52
(iv) We know that
(x – 1/x)2 = x2 + 1/x2 – 2
Substituting the values
= 14 – 2
= 12
So we get
x – 1/x = ± 2√3
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