**If x – y = 8 and xy = 5, find x**^{2} + y^{2}.

^{2}+ y

^{2}.

**Answer :**

We know that

**(x – y) ^{2} = x^{2} + y^{2} – 2xy**

It can be written as

x^{2} + y^{2} = (x – y)^{2} + 2xy

It is given that

x – y = 8 and xy = 5

Substituting the values

x^{2} + y^{2} = 8^{2} + 2 × 5

So we get

= 64 + 10

= 74

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