If x4y2z3 = 49392, find the values of x, y and z

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If x4y2z3 = 49392, find the values of x, y and z, where x, y and z are different positive primes.

Solution:

It is given that

x4y2z3 = 49392

We can write it as

x4y2z3 = 2 × 2 × 2 × 2 × 3 × 3 × 7 × 7 × 7

x4y2z3 = (2)4 (3)2 (7)3 ……. (1)

ML Aggarwal Solutions for Class 9 Maths Chapter 8 Image 73

Now compare the powers of 4, 2 and 3 on both sides of equation (1)

x = 2, y = 3 and z = 7

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