In the adjoining figure, D is a point on BC such that ∠ABD = ∠CAD. If AB = 5 cm, AC = 3 cm and AD = 4 cm, find
(i) BC
(ii) DC
(iii) area of ∆ACD : area of ∆BCA.
Solution:
More Solutions:
- CM and RN are respectively the medians of ∆ABC and ∆PQR.
- Medians AD and BE of ∆ABC meet at the point G.
- In the figure given below, AB, EF and CD are parallel lines.
- ∠A = 90° and AD ⊥ BC If BD = 2 cm and CD = 8 cm.
- A 15-meter high tower casts a shadow of 24 meters.
- In the figure, DE parallel BG, AD = 3 cm, BD = 4 cm and BC = 5 cm.