#### (a) In the figure given below, AB || DE, AC = , 3 cm, CE = 7.5 cm and BD = 14 cm. Calculate CB and DC.

#### (b) In the figure (2) given below, CA || BD, the lines AB and CD meet at G.

(i) Prove that ∆ACO ~ ∆BDO.

(ii) If BD = 2.4 cm, OD = 4 cm, OB = 3.2 cm and AC = 3.6 cm, calculate OA and OC.

**Solution:**

**More Solutions:**

- Straight line passing through the intersection of 2x + 5y – 4 = 0.
- Line perpendicular from the point (1, -2) on the line 4x – 3y – 5 = 0.
- The line through (0, 0) and (2, 3) is parallel.
- The points A (1, 3), B (3, -1) and C (-5, -5) is a right-angled triangle.
- A (-1, 3), B (4, 2), C (3, -2) are the vertices of a triangle.
- In the adjoining diagram, the coordinates of the points A, B and C.