In the given figure, sides BC, CA and AB of ∆ABC touch a circle at the points P, Q and R respectively. If PC = 5 cm, AR = 4 cm and RB = 6 cm, then the perimeter of ∆ABC is
(a) 60 cm
(b) 45 cm
(c) 30 cm
(d) 15 cm
Solution:
PQ is a tangent to a circle at point P. Centre of a circle is O. If ∆OPQ is an isosceles triangle, then ∠QOP is equal to
(a) 30°
(b) 60°
(c) 45°
(d) 90°
Solution:
More Solutions:
- A point P is 13 cm from the center of a circle.
- From a point outside a circle, with center O, tangents PA and PB are drawn.
- The figure given below shows two circles with centres A, B.
- Two circles with centers A and B touch externally.
- Two chords AB, CD of a circle intersect externally at a point P.
- Chord AB and diameter CD of a circle with centre O meet at P.