In the parallelogram ABCD, P is a point on the side AB and Q is a point on the side BC. Prove that
(i) area of ∆CPD = area of ∆AQD
(ii)area of ∆ADQ = area of ∆APD + area of ∆CPB.
Solution:
More Solutions:
- Prove that the quadrilateral is a parallelogram.
- Find the area of parallelogram ABCD.
- Prove that: area of ∆AER = area of ∆AFR.
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