In ∆ABC, AP: PB = 2 : 3. PO is parallel to BC and is extended to Q so that CQ is parallel to BA.

In ∆ABC, AP: PB = 2 : 3. PO is parallel to BC and is extended to Q so that CQ is parallel to BA. Find:
(i) area ∆APO : area ∆ABC.
(ii) area ∆APO: area ∆CQO. (2008)

Solution:

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