In the given figure, medians AD and BE of ∆ABC meet at the point G, and DF is drawn parallel to BE. Prove that
(i) EF = FC
(ii) AG : GD = 2 : 1
Solution:
A street light bulb is fixed on a pole 6 m above the level of the street. If a woman of height casts a shadow of 3 m, find how far she is away from the base of the pole.
Solution:
More Solutions:
- DE parallel BC. If DE = 6 cm, BC = 9 cm and area of ∆ADE = 28 sq. cm
- Prove that ∆ADE and ∆ABC are similar.
- In the given figure, AB and DE are perpendicular to BC.
- In the adjoining figure, ABC is a triangle. DE is parallel to BC.
- In ∆ABC, AP: PB = 2 : 3. PO is parallel to BC and is extended to Q so that CQ is parallel to BA.
- Determine the ratio of the areas of ∆AOB and ∆COD.