n(A ∪ B) = B (A) + n(B) – n(A ∩ B)

If ξ = {natural numbers between 10 and 40}
A = {multiples of 5} and
B = {multiples of 6}, then
(i) find A ∪ B and A ∩ B
(ii) verify that
n(A ∪ B) = B (A) + n(B) – n(A ∩ B).

Solution:

More Solutions:

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