O is the circumcentre of the triangle ABC and D is mid-point of the base BC. Prove that ∠BOD = ∠A.
Solution:
More Solutions:
- Given below, AB is a diameter of a circle with centre O.
- P is the point of intersection of the chords BC and AQ.
- CP bisects ∠ACB. Prove that DP bisects ∠ADB.
- Given below, chords AB and CD of a circle intersect at E.
- AE and BC intersect each other at point D. If ∠CDE = 90°.
- Calculate the perimeter of the cyclic quadrilateral PQRS.