(a) In the figure (i) given below, P is the point of intersection of the chords BC and AQ such that AB = AP. Prove that CP = CQ
(b) In the figure (i) given below, AB = AC = CD, ∠ADC = 38°. Calculate :
(i) ∠ABC (ii) ∠BEC.
Solution:
More Solutions:
- If the area of two similar triangles are 360 cm² and 250 cm².
- In the adjoining figure, D is a point on BC.
- In the adjoining figure, the diagonals of a parallelogram intersect at O.
- E is mid-point of BC. DE meets the diagonal AC at O.
- A point moves such that its distance from a fixed line AB.
- P is a fixed point and a point Q moves such that the distance PQ.