In a quadrilateral, ABCD∠B = 90° = ∠D. Prove that 2 AC² – BC2 = AB² + AD² + DC².
Solution:
More Solutions:
- The distance of the foot of the ladder.
- The distance of the girl from the starting point is
- If the length of the ladder is 15 m.
- Find the length of BC.
- Prove that AB2 – AC2 = BD2 – CD2.
- Which divide these sides in the ratio 2:1.
- Prove that 8PT² – 3PR² + 5PS².
- Prove that ∠ACD = 90°.
- Find the length of AD in terms of b and c.
- Find the length of AC.