ABCD is a square and the diagonals intersect at O. If P is a point on AB such that AO =AP, prove that 3 ∠POB = ∠AOP.
Solution:
More Solutions:
- Prove that 3(AB² + BC² + CA²) = 4(AD² + BE² + CF²).
- Prove that AB² + CD² = AD² + BC².
- Prove that 2 AC² – BC2 = AB² + AD² + DC².
- Prove that : DC² – BD² = 2AB. AD.
- Prove that AD² = AC² + BD.CD.
- Calculate the length of PR and QR.
- If AB = 6√3 cm, BC = 6 cm and AC = 12 cm
- The length of its diagonal is
- The length of the side of the rhombus is
- The length of the other diagonals is