In the given figure, ∆PQR is right angled at Q and points S and T trisect side QR. Prove that 8PT² – 3PR² + 5PS².
Solution:
More Solutions:
- Prove that BD = BC.
- Find these angles.
- Prove that it is a trapezium.
- Find the angles of the parallelogram.
- Calculate angles CDB and ADB.
- ABCD is a parallelogram with perimeter 40.
- If ∠ABD = 50°, find ∠DPC.
- Find angle BED represented by x.
- ABCD is a trapezium. Find the values of x and y.
- Prove that each angle of a rectangle is 90°.