Prove that ABC is an isosceles triangle.

In the given figure, D is mid-point of BC, DE and DF are perpendiculars to AB and AC respectively such that DE = DF. Prove that ABC is an isosceles triangle.

Solution:

More Solutions:

• Prove that (a) BP = CP
• Show that ∆ABD ≅ ∆ACE.
• Show that ∆ADE ≅ ∆BCE
• Prove that BC = 2AD.
• Which side of this triangle is longest?
• Which is the least angle.
• In ∆ ABC, AB = 8 cm, BC = 5.6 cm and CA = 6.5 cm.
• In ∆ABC, ∠A = 50°, ∠B= 60°
• The bisector of ∠A meets BC at D.
• Which is greater : BD or DC?