**(a) In the figure (1) given below, BC || AE and CD || BE. Prove that: area of ∆ABC= area of ∆EBD.**

**(b) In the llgure (2) given below, ABC is right angled triangle at A. AGFB is a square on the side AB and BCDE is a square on the hypotenuse BC. If AN ⊥ ED, prove that:**

**(i) ∆BCF ≅ ∆ ABE.**

**(ii)arca of square ABFG = area of rectangle BENM.**

**Solution:**

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