Prove that: area of ∆ABC= area of ∆EBD.

(a) In the figure (1) given below, BC || AE and CD || BE. Prove that: area of ∆ABC= area of ∆EBD.
(b) In the llgure (2) given below, ABC is right angled triangle at A. AGFB is a square on the side AB and BCDE is a square on the hypotenuse BC. If AN ⊥ ED, prove that:
(i) ∆BCF ≅ ∆ ABE.
(ii)arca of square ABFG = area of rectangle BENM.

Solution:

More Solutions:

• A median of a triangle divides it into two
• The mid-points of the sides of a triangle
• The ratio of area of ABEF
• Which of the following statements is not true?
• The area of parallelogram DEFC
• If area of || gm ABCD = 90 cm2, find:
• In the parallelogram ABCD
• Prove that area of ∆LZY = area of quad.
• If D is a point on the base BC
• Perpendiculars are drawn from a point.