**(a) In the figure (1) given below, the point D divides the side BC of ∆ABC in the ratio m : n. Prove that area of ∆ ABD: area of ∆ ADC = m : n.**

**(b) In the figure (2) given below, P is a point on the sidoBC of ∆ABC such that PC = 2BP, and Q is a point on AP such that QA = 5 PQ, find area of ∆AQC : area of ∆ABC.**

**(c) In the figure (3) given below, AD is a median of ∆ABC and P is a point in AC such that area of ∆ADP : area of AABD = 2:3. Find**

**(i) AP : PC (ii) area of ∆PDC : area of ∆ABC.**

**Solution:**

**More Solutions:**

- Construct a parallelogram ABCD with AB = 5.1 cm
- Which AB = 4.6 cm, BC = 3.2 cm and AC = 6.1 cm.
- AB = 4 cm, AC = 10 cm, BD = 6 cm. Measure BC.
- Diagonal BD = 4.4 cm. Measure the side AB.
- Measure one of the longer sides.
- Whose diagonals are 4 cm and 6 cm.
- Measure the acute angles of the parallelogram.
- Using ruler and compasses only, construct ABCD.
- Construct a rectangle ABCD
- Whose diagonals measures 6 cm.