**(a) In the figure (1) given below, ABCD is a parallelogram. Points P and Q on BC trisect BC into three equal parts. Prove that :**

**area of ∆APQ = area of ∆DPQ = 16 (area of ||gm ABCD)**

**(b) In the figure (2) given below, DE is drawn parallel to the diagonal AC of the quadrilateral ABCD to meet BC produced at the point E. Prove that area of quad. ABCD = area of ∆ABE.**

**(c) In the figure (3) given below, ABCD is a parallelogram. O is any point on the diagonal AC of the parallelogram. Show that the area of ∆AOB is equal to the area of ∆AOD.**

**Solution:**

**More Solutions:**

- Construct a parallelogram ABCD with AB = 5.1 cm
- Which AB = 4.6 cm, BC = 3.2 cm and AC = 6.1 cm.
- AB = 4 cm, AC = 10 cm, BD = 6 cm. Measure BC.
- Diagonal BD = 4.4 cm. Measure the side AB.
- Measure one of the longer sides.
- Whose diagonals are 4 cm and 6 cm.
- Measure the acute angles of the parallelogram.
- Using ruler and compasses only, construct ABCD.
- Construct a rectangle ABCD
- Whose diagonals measures 6 cm.