(a) In the figure (1) given below, two parallelograms ABCD and AEFB are drawn on opposite sides of AB, prove that: area of || gm ABCD + area of || gm AEFB = area of || gm EFCD.
(b) In the figure (2) given below, D is mid-point of the side AB of ∆ABC. P is any point on BC, CQ is drawn parallel to PD to meet AB in Q. Show that area of ∆BPQ = 12 area of ∆ABC.
(c) In the figure (3) given below, DE is drawn parallel to the diagonal AC of the quadrilateral ABCD to meet BC produced at the point E. Prove that area of quad. ABCD = area of ∆ABE.
Solution:
More Solutions:
- Construct a parallelogram ABCD with AB = 5.1 cm
- Which AB = 4.6 cm, BC = 3.2 cm and AC = 6.1 cm.
- AB = 4 cm, AC = 10 cm, BD = 6 cm. Measure BC.
- Diagonal BD = 4.4 cm. Measure the side AB.
- Measure one of the longer sides.
- Whose diagonals are 4 cm and 6 cm.
- Measure the acute angles of the parallelogram.
- Using ruler and compasses only, construct ABCD.
- Construct a rectangle ABCD
- Whose diagonals measures 6 cm.