(a) In the figure
(i) given below, ∠P = ∠RTS.
Prove that ∆RPQ ~ ∆RTS.
(b) In the figure (ii) given below,
∠ADC = ∠BAC. Prove that CA² = DC × BC.
Solution:
More Solutions:
- Straight line passing through the intersection of 2x + 5y – 4 = 0.
- Line perpendicular from the point (1, -2) on the line 4x – 3y – 5 = 0.
- The line through (0, 0) and (2, 3) is parallel.
- The points A (1, 3), B (3, -1) and C (-5, -5) is a right-angled triangle.
- A (-1, 3), B (4, 2), C (3, -2) are the vertices of a triangle.
- In the adjoining diagram, the coordinates of the points A, B and C.