(a) In the figure (i) given below, PT is a tangent to the circle. Find TP if AT = 16 cm and AB = 12 cm.
(b) In the figure given below, diameter AB and chord CD of a circle meet at P. PT is a tangent to the circle at T. CD = 7.8 cm, PD = 5 cm, PB = 4 cm. Find (i) AB. (ii) the length of tangent PT.
Solution:
In the adjoining figure, CBA is secant and CD is tangent to the circle. If AB = 7 cm and BC = 9 cm, then
(i) Prove that ∆ACD ~ ∆DCB.
(ii) Find the length of CD.
Solution:
More Solutions:
- In the figure given below, O is the centre of the circle.
- Given below, PQ is a diameter. Chord SR is parallel to PQ.
- AB is a diameter of the circle. If ∠ADC = 120°, find ∠CAB.
- ABCD is a quadrilateral inscribed in a circle with centre O.
- PQRS is a cyclic quadrilateral in which PQ = QR and RS is produced to T.
- Given below, O is the centre of the circle.