**By means of an example, show that sin (A + B) ≠ sin A + sin B.**

#### Answer :

A = 30° and B = 60°

LHS = sin (A + B)

= sin (30° + 60°)

= sin 90°

= 1

RHS = sin A + sin B

= sin 30° + sin 60°

= ½ + √3/2

= (1 + √3)/2

Hence, LHS ≠ RHS i.e. sin (A + B) ≠ sin A + sin B.

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