(2x + 3y + 4z) (4x2 + 9y2 + 16z2 – 6xy – 12yz – 8zx).
Answer :
(2x + 3y + 4z) (4x2 + 9y2 + 16z2 – 6xy – 12yz – 8zx)
It can be written as
= (2x + 3y + 4z) ((2x)2 + (3y)2 + (4z)2 – 2x × 3y – 3y × 4z – 4z × 2x)
By further calculation
= (2x)3 + (3y)3 + (4z)3 – 3 × 2x × 3y × 4z
So we get
= 8x3 + 27y3 + 64z3 – 72xyz
More Solutions:
- Trigonometric Ratios of Standard Angles
- Find the value of A if
- Find the value of θ (0° < θ < 90°) if:
- If A, B and C are the interior angles of a △ ABC
- The value of tan 30/cot60 is
- The value of (sin 45 + cos 45 ) is
- The value of tan² 30 – 4 sin² 45 is
- If A = 30, then the value of 2 sin A Cos A is
- The value of (sin 30 + cos 30) – (sin 60 + cos 60) is
- The value of √3 cosec 60 – sec 60 is