**Simplify the following:**

**…………………..**

**Answer :**

##### (i) It can be written as

= cos θ/cos θ + sin θ/cosec θ – 3 tan^{2} 30^{0}

= 1 + (sin θ × sin θ) – 3 (1/√3)^{2}

= sin^{2} θ + 1 – (3 × 1/3)

= sin^{2} θ + 1 – 1

= sin^{2} θ

##### (ii) It can be written as

= (sec θ cos θ tan θ)/(sin θ cosec θ tan θ) + cot θ/cot θ

So we get

= sec θ cos θ/sin θ cosec θ + 1

= 1/1 + 1

= 1 + 1

= 2

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