sin2 60° – cos2 45° + 3tan2 30°

Find the values of:

(i) sin² 60° – cos² 45° + 3tan² 30°
(ii)……………..
(iii) sec 30° tan 60° + sin 45° cosec 45° + cos 30° cot 60°

Answer :

(i) sin² 60° – cos² 45° + 3tan² 30°

Therefore, sin² 60° – cos² 45° + 3tan² 30° = 1¼

(iii) sec 30° tan 60° + sin 45° cosec 45° + cos 30° cot 60°

= 2 + 1 + ½ = 3 + ½ = (6 + 1)/2

= 7/2 = 3½

Thus,

sec 30° tan 60° + sin 45° cosec 45° + cos 30° cot 60° = 3½

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