**Find the values of:**

(i) sin^{2} 60° – cos^{2} 45° + 3tan^{2} 30°

(ii)……………..

(iii) sec 30° tan 60° + sin 45° cosec 45° + cos 30° cot 60°

**Answer :**

**(i)** sin^{2} 60° – cos^{2} 45° + 3tan^{2} 30°

Therefore, sin^{2} 60° – cos^{2} 45° + 3tan^{2} 30° = 1¼

**(iii)** sec 30° tan 60° + sin 45° cosec 45° + cos 30° cot 60°

= 2 + 1 + ½ = 3 + ½ = (6 + 1)/2

= 7/2 = 3½

Thus,

sec 30° tan 60° + sin 45° cosec 45° + cos 30° cot 60° = 3½

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