Solve: 2 (sin6 θ + cos6 θ) – 3 (sin4 θ + cos4 θ) + 1 = θ

2 (sin⁶ θ + cos⁶ θ) – 3 (sin⁴ θ + cos⁴ θ) + 1 = θ

Solution:

2 (sin⁶ θ + cos⁶ θ) – 3 (sin⁴ θ + cos⁴ θ) + 1 = θ
L.H.S = 2 (sin⁶ θ + cos⁶ θ) – 3 (sin⁴ θ + cos⁴ θ) + 1

If cot θ + cos θ = m, cot θ – cos θ = n, then prove that (m² – n²)² = 16 run.

Solution:

cot θ + cos θ = m…..(i)
cot θ – cos θ = n……(ii)
Adding (i)&(ii) we get

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