Solve: (sec A – 1)/(sec A + 1) = (1 – cos A)/(1 + cos A).

by

(i) \frac { secA-1 }{ secA+1 } =\frac { 1-cosA }{ 1+cosA }
(ii) \frac { { tan }^{ 2 }\theta }{ { (sec\theta -1) }^{ 2 } } =\frac { 1+cos\theta }{ 1-cos\theta }
(iii) { (1+tanA) }^{ 2 }+{ (1-tanA) }^{ 2 }=2{ sec }^{ 2 }A
(iv) { sec }^{ 2 }A+{ cosec }^{ 2 }A={ sec }^{ 2 }A{ .cosec }^{ 2 }A

Solution:

(i) \frac { secA-1 }{ secA+1 } =\frac { 1-cosA }{ 1+cosA }
L.H.S = \frac { secA-1 }{ secA+1 }

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 18 Trigonometric Identities Ex 18 Q16.1

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 18 Trigonometric Identities Ex 18 Q16.2

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