(i) (sec A + tan A) (1 – sin A) = cos A
(ii) (1 + tan2 A) (1 – sin A) (1 + sin A) = 1.
Solution:
(i) (sec A + tan A) (1 – sin A) = cos A
L.H.S. = (sec A + tan A) (1 – sin A)
(i) tan A + cot A = sec A cosec A
(ii) (1 – cos A)(1 + sec A) = tan A sin A.
Solution:
(i) tan A + cot A = sec A cosec A
L.H.S. = tan A + cot A
More Solutions:
- Find the number of lead shots dropped into the vessel.
- How many such spheres can be obtained.
- The surface area of a solid metallic sphere is 1256 cm².
- what time will the level of water in the pond rise by 21 cm.
- A cylindrical can whose base is horizontal and of radius 3.5 cm.
- If radius is halved and height is doubled.