Solve simultaneous linear equations: (i) (3a – 2b)2 + 3(3a – 2b) – 10

Solve simultaneous linear equations:

(i) (3a – 2b)² + 3(3a – 2b) – 10
(ii) (x² – 3x) (x² – 3x + 7) + 10

Solution:

(i) (3a – 2b)² + 3(3a – 2b) – 10
Let us assume, (3a – 2b) = p
p² + 3p – 10
p² + 5p – 2p – 10
Take out common in all terms,
p(p + 5) – 2(p + 5)
(p + 5) (p – 2)
Now, substitute the value of p
(3a – 2b + 5) (3a – 2b – 2)
(ii) (x² – 3x) (x² – 3x + 7) + 10
(x² – 3x) (x² – 3x + 7) + 10
Let us assume, (x² – 3x) = q
q (q + 7) + 10
q² + 7q + 10
q² + 5q + 2q + 10
q(q + 5) + 2(q + 5)
(q + 5) (q + 2)
Now, substitute the value of q
(x² – 3x + 5) (x² – 3x + 2)

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