Solve simultaneous linear equations:
(i) b(c -d)2 + a(d – c) + 3c – 3
(ii) x3 – x2 – xy + x + y – 1
Solution:
(i) b(c -d)2 + a(d – c) + 3c – 3d
Above terms can be written as,
b(c – d)2 – a(c – d) + 3c – 3d
b(c – d)2 – a(c – d) + 3(c – d)
Take out common in both terms,
(c – d) [b(c – d) – a + 3]
(c – d) (bc – bd – a + 3)
(ii) x3 – x2 – xy + x + y – 1
x3 – x2 – xy + x + y – 1
Rearrange the above terms we get,
x3 – x2 – xy + y + x – 1
Take out common in both terms,
x2(x – 1) – y(x – 1) + 1(x – 1)
(x – 1) (x2 – y + 1)
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