Solve: tan2 theta/(1 + tan2 theta)

\frac { { tan }^{ 2 }\theta }{ 1+{ tan }^{ 2 }\theta } is equal to
(a) 2 sin2 θ
(b) 2 cos2 θ
(c) sin2 θ
(d) cos2 θ

Solution:

\frac { { tan }^{ 2 }\theta }{ 1+{ tan }^{ 2 }\theta }

ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 18 Trigonometric Identities MCQS Q3.1

= =\frac { { sin }^{ 2 }\theta }{ 1 } ={ sin }^{ 2 }\theta (c)

(cos θ + sin θ)2 + (cos θ – sin θ)2 is equal to
(a) – 2
(b) 0
(c) 1
(d) 2

Solution:

(cos θ + sin θ)2 + (cos θ – sin θ)2
= cos2 θ + sin2 θ + 2 sin θ cos θ + cos2 θ + sin2 θ – 2 sin θ cos θ
= 2(sin2 θ + cos2 θ)
= 2 × 1 = 2 (d)
(∵ sin2 θ + cos2 θ = 1)

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